c^2+1c+40=0

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Solution for c^2+1c+40=0 equation:


Simplifying
c2 + 1c + 40 = 0

Reorder the terms:
40 + 1c + c2 = 0

Solving
40 + 1c + c2 = 0

Solving for variable 'c'.

Begin completing the square.

Move the constant term to the right:

Add '-40' to each side of the equation.
40 + 1c + -40 + c2 = 0 + -40

Reorder the terms:
40 + -40 + 1c + c2 = 0 + -40

Combine like terms: 40 + -40 = 0
0 + 1c + c2 = 0 + -40
1c + c2 = 0 + -40

Combine like terms: 0 + -40 = -40
1c + c2 = -40

The c term is 1c.  Take half its coefficient (0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
c + 0.25 + c2 = -40 + 0.25

Reorder the terms:
0.25 + c + c2 = -40 + 0.25

Combine like terms: -40 + 0.25 = -39.75
0.25 + c + c2 = -39.75

Factor a perfect square on the left side:
(c + 0.5)(c + 0.5) = -39.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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